几何尺寸与公差论坛

 找回密码
 注册
查看: 587|回复: 0

2002 msjc code seminar notes

[复制链接]
发表于 2009-9-7 08:25:41 | 显示全部楼层 |阅读模式
2002 msjc code seminar notes
i am trying to find where the 0.746 factor comes from when calculating the allowable stress fa for asd of unreinforced masonry bearing walls in the following example problems:
example 2a, page 6
example 2b, page 11
example 2c, page 15
i did look in the aci530/asce5-02/tms 402-02 building code requirements for masonry structure, page c-25 eq. (2-12) but didn't find anything.
thanks in advance for pointing me in the right direction.

additional question:
in example problem 2c, page 16, regarding the stability equation, the notes state "moments and axial forces from lateral loads are not included in this (stability) check."
why?  in a wall just on the verge of instablity couldn't lateral loads be enough to "push it over the edge"?
they are just showing you the math....
the first part of the term - 0.25f'm
the second part of the term - (1-(h/140r)^2) = 0.746
they separate the two to give you a feel for the effect of the slenderness on the total allowable stress.
jae,
now that you turned on the light switch, it seems trivial.  it seems that i looked at that for hours, i must have been in a trance.
thanks
well..honestly, i poured over it for some time looking for the damned 0.746 source as well.
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|小黑屋|几何尺寸与公差论坛

GMT+8, 2024-11-16 02:47 , Processed in 0.034893 second(s), 19 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2023 Discuz! Team.

快速回复 返回顶部 返回列表