solving for impact loading

huangyhg

solving for impact loading
i am doing an overhead steel beam that will have a fall arrest system that will run along the bottom flange of the beam.  how do you determine the actual force?  up here in canada we used to have a factor of 1.65 for loading lasting less than 10 min.  this is a project for the us.  
basically, if a 200 lbs man fell what would the force be?  would it be as simple as f=ma? or is there a factor to use?
thanks
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i believe we typically use a load of 1.5 kips in any direction.  you can lower it if you meet certain criteria, but that is a good starting point.