几何尺寸与公差论坛

 找回密码
 注册
查看: 433|回复: 0

ibc 2000 1605.3.1.1

[复制链接]
发表于 2009-9-9 18:38:50 | 显示全部楼层 |阅读模式
ibc 2000 1605.3.1.1
supposedly this section gives you a break by allowing two or more transient loads to be multiplied by .75. however, the combined load cannot be less than d+e, without the .7 factor applied to e. this creates a new load combination that is more conservative than any of the combinations in formulas 16-7 thru 16-12. therefore, by trying to take advantage of their 'break', i have actually hurt myself by having to use this new load combination. am i missing something?
for allowable combinations i think it means:
to use d+0.75x(e+ (other transient loads)).
do not use d+0.75x(0.7e + (other transient loads)).
(d+0.7e) must also be checked, and (0.6d+0.7e).
not d+e.
thank you haynewp. what you say makes sense. i think that considering how much these equations are used, it would be better if the code wrote out all of the various combinations rather than turning it into a riddle.
mrengineer-
you've hit on a subject that i've long pondered....how the code is written in language rather than a logical flow chart diagram or other some sort of graphical mechanism whereby a strict logical process can be followed.
instead, there are numerous paragraphs and words that seem to imply concepts, but require lots of interpretation.  overall, i think the code writing dudes have done a magnificent job of keeping it to a point just this side of sanity....
are they toying with us?
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|小黑屋|几何尺寸与公差论坛

GMT+8, 2025-1-19 07:29 , Processed in 0.110370 second(s), 20 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2023 Discuz! Team.

快速回复 返回顶部 返回列表