几何尺寸与公差论坛

 找回密码
 注册
查看: 972|回复: 0

expected overall compliance

[复制链接]
发表于 2009-9-5 20:55:10 | 显示全部楼层 |阅读模式
expected overall compliance
dear all,
if i test a sample of material with multiple specified parameters i can calculate the expected compliance for each parameter.
e.g.
parameter 1 is expected to comply 90% of the time
parameter 2 is expected to comply 95% of the time
parameter 3 is expected to comply 85% of the time
if any parameter fails the overall result for a sample fails.
so from the above information is it possible to calculate the expected compliance of a sample with all respect to all parameters?
tia hugh
that depends on whether there is any correlation between the parameters.
if they are truly independent then the probability of a pass is 73%
cheers
greg locock
greg,
thanks for the response
i think i get and grasp your logic and get an answer of 72.675%
thus;
85% - (85% of 10%) = 85% - 8.5% = 76.5%
76.5% - (76.5% of 5%) = 76.5% - 3.825% = 72.675% (=73ish%)
am i correct in this?
the parameters are not independent (of course)!
kind regards hugh,
well you got the right answer, so in the new maths that means you understand it.
in the old days
p(a and b and c)=p(a)*p(b)*p(c)
if they are not independent and you understand the physical dependency then monte carlo modelling is often a good way to understand what is going on.
if on the other hand you just have a statistical description of the interrelationship then draw a venn diagram and sum appropriately.
cheers
greg locock
greg,
thanks for your help again.
p(a)*p(b)*p(c) looks less complicated.
seems i am going through 'old days' without actually having lived them!
much appreciated.
regards hugh
it just goes to show that not everything that is "new" is actually improved.  while it might be fodder for a separate thread,  to the old math.  i can tell i am going to have fun when it comes to work with my son through the new math.
regards,
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|小黑屋|几何尺寸与公差论坛

GMT+8, 2024-5-6 18:27 , Processed in 0.034722 second(s), 19 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2023 Discuz! Team.

快速回复 返回顶部 返回列表