【转帖】solidworks 二次开发困扰很久 的一个问题！！！！

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solidworks 二次开发困扰很久 的一个问题！！！！
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在装配体中插入了两个零件，点击其中一个零件零件，点击工具栏里的旋转零件，然后选择“由三角形x，y，z”，然后在三个输入框里任意输入三个角度，应用后，零件旋转。但是如果将这个操作录成宏，再执行，零件并没有旋转，因为打开宏可以看到语句是：
% ~" ?) e0 s$ e4 l7 l6 o% opart.rotatecomponent
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就是说旋转的角度参数在这个语句中并没有。那么旋转应该用什么语句呢，还是在sw的执行函数中没有这个？
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1 z* ^+ w1 o: h3 t) s/ s0 }, ~请教高手！5 l. r8 w6 j) p7 d9 {+ k
+ `6 \7 u- k, w3ks


你好
$ n% {2 k- _4 e7 ~% v我也在研究这个问题。
) j: }0 w2 i( r% t! p- u5 d我也想对运动进行二次开发
# w7 s: v" z- ^. b我的qq号是460431336
你们好，我这方面的新手，我不知道你们问题的解决方法。我现有一个问题，如何得到三维图形的尺寸？
顶一下！~  同问此问题   我也被这个困扰好久了~  有没有高人知道阿……
汇集最新内容：     
下面时我录的部分，应该由另外的语句记录了角度之类的参数， 接着是执行这个动作。
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set swapp = application.sldworks
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7 i( a1 z& p1 }) p0 n0 q3 i5 pset part = swapp.activedoc
8 i5 y; p0 i2 t8 w! z5 |) sset selmgr = part.selectionmanager! i* a+ p; z9 s, `5 _+ z
swapp.activedoc.activeview.framestate = 13 l. ~! d  w! d- @+ r
part.clearselection2 true3 b- _  h' |$ d: a/ ?" |
boolstatus = part.extension.selectbyid2("拉伸1", "solidbody", -0.008353456370571, 0.009631396338079, 0.01000000000005, true, 0, nothing, 0): }8 e. x5 i: d. d8 x% p
boolstatus = part.extension.selectbyid2("上视基准面", "plane", 0, 0, 0, true, 0, nothing, 0)
2 a: h& v8 s5 k2 o9 r' iboolstatus = part.extension.selectbyid2("", "face", -0.01463440088054, 0.02764117647052, 0.006059731040523, true, 0, nothing, 0)
' y3 h2 e( j& r3 m7 c8 f; sdim component as object: s3 b' ~, i! a! t( a
dim featuredata as object
. q. _3 f! e- kpart.clearselection2 true
! k; ]& ]( |9 d* {7 wboolstatus = part.extension.selectbyid2("拉伸1", "solidbody", -0.008353456370571, 0.009631396338079, 0.01000000000005, false, 1, nothing, 0)6 z- [3 i) `+ j4 r& ^* g. ^8 \
set feature = part.featuremanager.insertmovecopybody2(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, false, 1); ]5 o" o: l& m* m
set featuredata = feature.getdefinition
0 `1 k. _0 b3 x& ^boolstatus = part.extension.selectbyid2("上视基准面", "plane", 0, 0, 0, false, 1, nothing, 0)
7 k- k4 c$ ?3 l$ w  c' aboolstatus = part.extension.selectbyid2("", "face", -9.338235294118e-04, 0.02764117647059, 0.005, true, 1, nothing, 0)0 ]% g' n* ]! l& k" o+ @
featuredata.addmate empty, 6, 1, 0, 0.8901179185171, longstatus
- c) d* y9 b1 k$ ffeature.modifydefinition featuredata, part, component, r2 o  t' r/ f
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end sub
look up the help file first  p5 j7 f- @. g" w, b
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1 [: s/ b/ [% g8 {to move an assembly component, you can use
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% {6 k1 `; [1 e  f' m the dragoperator object. this allows you to# i8 o- o' q' e% ?
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apply a transform to an assembly component
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# q8 c7 g/ x. g- g- i1 t4 z8 j4 por set of assembly components.1 c# o5 ]9 x5 u. i0 z
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the dragoperator object is a powerful and functional6 m: d; m  y! o% q4 u: r; k3 e8 p
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api. it has the ability to detect+ d" j6 h* t( e
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collisions and monitor dynamic clearances.
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this functionality is the user-interface equivalent of& j! l% ^8 ]- d7 k
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interactively dragging assembly components.
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as such, this api honors all mates in the8 {2 k& z" u- y  ^8 g5 b6 v# n. w  y
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assembly.
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in some cases, this may be too much functionality.5 r# i3 x4 w& {: o; i
; l  d" k- t2 w for example, to animate exploding an assembly,* `" b: q/ u. e: {' k1 ~: h' v# ^
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you want to set each component transform and7 p# o8 t2 j# j3 k' a* w- }3 s) q
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ignore all assembly mates.
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! \. v: m+ j: v3 g5 a& n9 u; |a presentation transform is a graphical representation./ c2 @" h! t  u1 t4 j
+ c& \3 e# f3 l. w! @this blindly applies a transformation to the* o' s9 @  h/ a. a% w  g! {1 u
. z4 u, x3 p2 e" u' sgraphical display of an assembly component. the2 j+ t& o/ x, u! |
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underlying transform of the model data is not affected.
help has almost everything you need
geminilele:. ?/ j, _! z' ?$ g: w
     many thanks! i got it~   and i recognized the important of the help files......   thanks again for your help.  ^^
very glad you can catch that : ), i'm also been taught as this. look up your help, you may get almost everything .
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