【转帖】为什么提示“类型不匹配”？
 

为什么提示“类型不匹配”？
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为什么提示“类型不匹配”？
做两个圆求交点，然后判断，两圆有交点时，程序运行正常。
问题出在没有交点时，我本想输出对话框提示，然而系统报警，说“类型不匹配”，各位看看怎么回事？
private function getfsupportcenter(bsupportcenter as variant, fswingbasepoint as variant) as variant
dim testlayer as acadlayer
dim objcircle1 as acadcircle '辅助圆
dim objcircle2 as acadcircle
dim swinglength as double
dim swingpitch as double
dim pt(0 to 2) as double
set testlayer = thisdrawing.layers.add("非显示层") '辅助线位于非显示层
testlayer.color = acred
thisdrawing.application.activedocument.activelayer = testlayer '激活图层
testlayer.layeron = true
swinglength = 2607
swingpitch = 3250
set objcircle1 = thisdrawing.modelspace.addcircle(fswingbasepoint, swinglength) '作辅助线
set objcircle2 = thisdrawing.modelspace.addcircle(bsupportcenter, swingpitch)
dim intpoints as variant
intpoints = objcircle2.intersectwith(objcircle1, acextendnone) '获取交点并判断
if vartype(intpoints) = vbempty then
msgbox "没有交点!"
elseif bsupportcenter(1) = fswingbasepoint(1) then
for i = lbound(intpoints) + 1 to ubound(intpoints) step 3
on error resume next
if intpoints(i) < bsupportcenter(1) then
pt(0) = intpoints(i - 1): pt(1) = intpoints(i): pt(2) = intpoints(i + 1)
getfsupportcenter = pt '函数返回值
end if
next
else
for i = lbound(intpoints) to ubound(intpoints) step 3
on error resume next
if (intpoints(i + 1) - fswingbasepoint(1)) / (bsupportcenter(1) - fswingbasepoint(1)) - (intpoints(i) - fswingbasepoint(0)) / (bsupportcenter(0) - fswingbasepoint(0)) < 0 then
pt(0) = intpoints(i): pt(1) = intpoints(i + 1): pt(2) = intpoints(i + 2)
getfsupportcenter = pt '函数返回值
end if
next
end if
'objcircle1.delete
'objcircle2.delete
end function
sub trial()
dim a as variant
dim b as variant
dim c as variant
a = thisdrawing.utility.getpoint(, "后支撑碗中心：")
b = thisdrawing.utility.getpoint(, "前摆杆上铰接点：")
c = getfsupportcenter(a, b)
msgbox "前支撑碗中心坐标：" & c(0) & "," & c(1) & "," & c(2)
end sub