【转帖】有关拖动的问题 - 精华帖集合
 

有关拖动的问题 - 精华帖集合
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有关拖动的问题
重载sampler函数时，获取角度应该怎么做？调用acquireangle方法好像得到的是距离而不是角度
acquireangle方法是在什么地方的？我没见过。
c#最适合开发autocad，因为它拥有vb容易的特点，却具有vc++的强大功能。
按照arx例子写了一个块的拖动类，有两个动作：移动和旋转
移动取点，旋转取角度
代码中promptpointresult res = prompts.acquirepoint(jigopts);是取点的动作，想改为acquireangle一直没有成功
代码如下：
using system;
using autodesk.autocad.databaseservices;
using autodesk.autocad.geometry;
using autodesk.autocad.editorinput;
using autodesk.autocad.applicationservices;
namespace tlscad
{
public class blockrefjig:entityjig
{
point3d mposition;
double mangle;
int mpromptcounter;
public blockrefjig(objectid id):base(new blockreference(new point3d(0,0,0),id))
{
mposition=new point3d(0,0,0);
mangle=0;
}

protected override samplerstatus sampler(jigprompts prompts)
{
jigpromptoptions jigopts = new jigpromptoptions();

if(mpromptcounter == 0)
{
jigopts.userinputcontrols = (userinputcontrols.accept3dcoordinates | userinputcontrols.nozeroresponseaccepted | userinputcontrols.nonegativeresponseaccepted );
jigopts.message = "\n请输入基点:";
promptpointresult dres = prompts.acquirepoint(jigopts);
point3d positiontemp = dres.value;
if(positiontemp != mposition)
{
mposition = positiontemp;
}
else
return samplerstatus.nochange;
if(dres.status == promptstatus.cancel)
return samplerstatus.cancel;
else
return samplerstatus.ok;


}
else if (mpromptcounter == 1)
{
jigopts.userinputcontrols = (userinputcontrols.accept3dcoordinates | userinputcontrols.nonegativeresponseaccepted);
jigopts.basepoint = mposition;
jigopts.usebasepoint = true;
jigopts.message = "\n请输入旋转角度:";
double angletemp = -1;
promptpointresult res = prompts.acquirepoint(jigopts);
point3d anglepnt = res.value;
angletemp = anglepnt.getvectorto(mposition).angleonplane(
new plane(
application.documentmanager.mdiactivedocument.database.ucsorg,
application.documentmanager.mdiactivedocument.database.ucsxdir,
application.documentmanager.mdiactivedocument.database.ucsydir
));
if (angletemp != mangle)
mangle = angletemp;
else
return samplerstatus.nochange;
if(res.status == promptstatus.cancel)
return samplerstatus.cancel;
else
return samplerstatus.ok;

}
else
{
return samplerstatus.nochange;
}


}
protected override bool update()
{

try
{
((blockreference)entity).position=mposition;
((blockreference)entity).rotation =mangle;
}
catch(system.exception)
{
return false;
}

return true;
}
public void setpromptcounter(int i)
{
mpromptcounter = i;
}
public entity getentity()
{
return entity;
}
}
}
复制代码
看着有点儿晕哟，先学习学习：）
刚刚试用了2007，拖动的bug已经搞定：）
using system;
using autodesk.autocad.databaseservices;
using autodesk.autocad.geometry;
using autodesk.autocad.editorinput;
using autodesk.autocad.applicationservices;
namespace tlscad
{
public class blockrefjig:entityjig
{
point3d mposition;
double mangle;
int mpromptcounter;
public blockrefjig(objectid id):base(new blockreference(new point3d(0,0,0),id))
{
mposition=new point3d(0,0,0);
mangle=0;
}

protected override samplerstatus sampler(jigprompts prompts)
{

if(mpromptcounter == 0)
{
jigpromptpointoptions jigopts = new jigpromptpointoptions();
jigopts.userinputcontrols = (userinputcontrols.accept3dcoordinates | userinputcontrols.nozeroresponseaccepted | userinputcontrols.nonegativeresponseaccepted );
jigopts.message = "\n请输入基点:";
promptpointresult res = prompts.acquirepoint(jigopts);
point3d positiontemp = res.value;
if(positiontemp != mposition)
{
mposition = positiontemp;
}
else
return samplerstatus.nochange;
if(res.status == promptstatus.cancel)
return samplerstatus.cancel;
else
return samplerstatus.ok;


}
else if (mpromptcounter == 1)
{
jigpromptangleoptions jigopts = new jigpromptangleoptions();
jigopts.userinputcontrols = (userinputcontrols.accept3dcoordinates | userinputcontrols.nonegativeresponseaccepted);
jigopts.basepoint = mposition;
jigopts.usebasepoint = true;
jigopts.message = "\n请输入旋转角度:";
promptdoubleresult res = prompts.acquireangle(jigopts);
double angletemp = res.value;
if (angletemp != mangle)
mangle = angletemp;
else
return samplerstatus.nochange;
if (res.status == promptstatus.cancel)
return samplerstatus.cancel;
else
return samplerstatus.ok;
}
else
{
return samplerstatus.nochange;
}


}
protected override bool update()
{

try
{
((blockreference)entity).position=mposition;
((blockreference)entity).rotation =mangle;
}
catch(system.exception)
{
return false;
}

return true;
}
public void setpromptcounter(int i)
{
mpromptcounter = i;
}
public entity getentity()
{
return entity;
}
}
}
复制代码
嗯 [ ]
关于拖动
继承 inherits entityjig 可以实现拖动， 继承 inherits drawjig 也可以实现。
老兄,如何调用此类