(defun c: aaa())这样定义的函数不能被调用？
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(defun c: aaa())这样定义的函数不能被调用？
(defun c:aaa()
(princ "aaa")
)
(defun c:bbb()
(aaa)
)
函数aaa能这样被调用吗？
在cad的命令行调用
(defun c:aaa()
(princ "aaa")
)
(defun c:bbb()
(c:aaa)
)
--------------------
(defun aaa()
(princ "aaa")
)
(defun c:bbb()
(aaa)
)
(defun c:aaa()
(princ "aaa")
)
(defun c:bbb()
(c:aaa)
)
这样就行了
progress every day!!!
简单明了，支持一下
勤能补拙
支持下
(defun c:aaa()
(princ "aaa")
)
(defun c:bbb()
(c:aaa)
)
--------------------
(defun aaa()
(princ "aaa")
)
(defun c:bbb()
(aaa)
)