huangyhg

elastic curve
what will be the elastic curve of this beam
if i read the symbol at "b" correctly, the joint can develop moment and horizontal force, but no vertical. correct? sorry, but i have not seen this notation before.
mike mccann
mmc engineering
you could treat it as a plain catilever with a fully fixed, a downward point load w at b and an upward point load w at mid-span.
a solution of this problem is in the first site below :
pardon my ignorance but wouldn't this be a mechanism? at least for small deflections?
homework question....
i assume the op is asking how to arrive at the answers that are given below.
the problem has its basis in the elastic theory of beam bending. please see attached scan for some information regarding this. also:
msquared48
mike, i also haven't seen this notation before. i just realized doing work from softwares only made me loose o basics of statics. so i started to study own my own to take the rust off. i am trying to solve this with moment area method. can you draw out elastic curve for this or try to solve it ! !
kootenaykid
how can you change this to fixed end etc? i do not buy that
dhkahn i have great respect for you. too many engineers forget the basis of their computer calculations and end up losing the grasp on the real core aspects on which everything else is built.
as with the beam restraint conditions i think they are both s/s roller support allowing lateral movement (no moment at this point due to it being simply supported.
try drawing out the deflected shapes and approximates of the bending moments to see whats really happening.
lt.
this may shed some light on the problem:
for some reason my old post posted as part of my last post please ignore the text after the web link
pst
thanks prex.
the spread sheet gave me the shape of elastic curve and after that it was easy. got all answers matched.
dgkhan,
you don't buy my method????
your problem is statically determinate. you can work out the moment diagram in about 30 seconds flat. if you work out the moment diagrams for your example, and for the simplification that i suggested, you will find that they are identical. and, if the moment diagrams are identical, then so are the deflected shapes.
you could have solved this by the superposition of a couple of formulas straight out of the steel manual.

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