yang686526

【求助】sw的二次开发，帮忙看看
www.dimcax.com
我写了一段程序，但运行就出错，帮忙分析一下吧。初学sw的二次开发，大家别见笑
) }9 v- k2 o0 t0 l1 c# j& ?& d lpmodeldoc m_modeldoc = null;
0 r( v! t s. j: f7 v hresult hres = noerror; 7 n' w2 y/ i5 k( c8 n
hres = (theapplication->getswapp())->get_iactivedoc( [$m_modeldoc )] // retrieve imodeldoc pointer - z3 b/ g1 i+ i$ t8 q' ]7 v
if( m_modeldoc == null ) 1 a" y# k1 r0 j% s- h$ z h
return;
2 y2 k+ ~1 y" f; q: t lpconfiguration m_config = null;
' c5 ]; b5 p% }+ i) f$ [3 n hres = m_modeldoc->igetactiveconfiguration([$m_config)]
8 u; m. \) a; ~ lpcomponent2 m_component = null;
4 z# z0 h' }: z7 d lpmathtransform m_math = null; : o& @7 y) `( g* ], m4 l
double *p = new double[3]; 9 m$ g4 e3 q) l) \, h
p[0] = 0; 7 m5 z$ m$ c# \! h2 k; @$ i
p[1] = 0; 3 j3 y3 a1 x* j
p[2] = 0;
9 y! b6 i5 |3 z, u. e lpmathutility mathutility; 1 t: c: p) t$ k- m, e
(theapplication->getswapp())->igetmathutility([$mathutility)]
, g. p$ t3 w% v( f6 v lpmathpoint* point;
9 v: y3 i, b' o* k. {7 w mathutility->icreatepoint(p, point);
1 d8 d. t! j4 z p[0] = 1; 9 z6 i3 ^ u: _9 f
p[1] = 0;
* i5 k: \! k. d; w2 q p[2] = 0; ^1 @) ^; n, p2 f( p$ u
lpmathvector* vector;
1 w+ g `, d, f 6 k7 j9 x+ x, s4 g) z
mathutility->icreatevector(p, vector);  
! r0 |8 k2 p5 o$ o9 q4 h2 a2 l + j8 }7 {) n* d5 s
double angle; " o/ n% }2 p9 ?3 l
lpmathtransform transform; + e2 _" u8 f% o# b8 d7 w h% d

+ }3 {0 x6 w: r2 t8 c8 s9 x mathutility->icreatetransformrotateaxis ( *point, *vector, 10* 3.14159 /180, [$transform )]
# x8 z1 v5 f/ b* u variant_bool retval; 6 f( \9 j8 u% z; p. s e) b* y

; k7 y: ]: x" j! b- _8 p; q" t if(m_config->igetrootcomponent2(&m_component) == s_ok )
9 u! p+ @- e5 r% ^3 j q3 r. x {
: ~4 f/ z$ {/ t m_component->settransformandsolve2(transform, [$retval)] 5 d0 w5 ]; b. {. r0 a6 e3 s8 k, j
} 6 t2 j t! a4 f2 m
m_modeldoc->release(); 7 b+ j% o e" s5 }
m_config->release(); # o v, m1 ^* h; j! c4 ]) r
m_component->release();