几何尺寸与公差论坛------致力于产品几何量公差标准GD&T (GDT:ASME)|New GPS(ISO)研究/CAD设计/CAM加工/CMM测量  


返回   几何尺寸与公差论坛------致力于产品几何量公差标准GD&T (GDT:ASME)|New GPS(ISO)研究/CAD设计/CAM加工/CMM测量 » 三维空间:产品设计或CAX软件使用 » CAD设计 » 产品功能分析
用户名
密码
注册 帮助 会员 日历 银行 搜索 今日新帖 标记论坛为已读


回复
 
主题工具 搜索本主题 显示模式
旧 2009-09-07, 10:03 PM   #1
huangyhg
超级版主
 
huangyhg的头像
 
注册日期: 04-03
帖子: 18592
精华: 36
现金: 249466 标准币
资产: 1080358888 标准币
huangyhg 向着好的方向发展
默认 calculating reinforcing actual stress

calculating reinforcing actual stress
how do you calculate the actual stress in reinforcing under a given load? i have plenty of references showing how to get the capacity, but not the actual stress.
i know stress is p/a + m/s.
but let's say we have a reinforcing bar in the middle of a 12x12 beam/column.
for sake of this example what if p is zero and m is large.
i guess i'm confusing myself on the basics here with the situation where the reinforcing is at the c.g. of the section, which i presume is not the neutral axis.
if i missed some required information feel free to state some assumption, hopefully i can figure this out with a nudge in the right direction.
i'm doing this exercise in the first place because part of the code i'm working uses the actual reinforcing stress to calculate the required lap length.
sounds like you've never quite mastered or were never shown the strain compatibility concept. check out some older concrete design books such as wang and salmon in the 80s.
otherwise check out how a moment interaction diagram is developed as it is quite similar to what you want.
regards,
qshake
eng-tips forums:real solutions for real problems really quick.
stress is proportional to strain, in the elastic range (which is the only time you would calculate an actual stress in a reinforcing bar).
for bending, the further you are from the neutral axis, the larger the strain, and therefore, the larger the stress.
for axial loads, strain in the reinforcing bar must be the same as strain in the concrete.
qshake's suggestion is good--any reinforced concrete textbook should cover this stuff.
daveatkins
thanks guys. i'll try looking again, but like you said i am missing something in the basic concept.
when you construct the interaction diagram you are dealing with strains/stresses assuming a stress/strain in either the concrete or steel (either the steel reached it's allowable limit or the concrete did). really you start (at least i did when i made the interaction diagram) with assuming various values of k (various points for the neutral axis) and then go through all the compatibility equations to come up with the axial-moment capacity.
that approach does not seem to work for what i am talking about here. the concrete or steel would not be at one of the limits. let's say i calculate the stress at the extreme fiber of the concrete using p/a + m/s to give the stress in the concrete at the face. how do i get the neutral axis corresponding to that point, so i can calculate the corresponding stress in the steel?
like you said there's a basic point that i didn't imprint here.
if you read a reinforced concrete textbook it will explain it. it's difficult to answer in forum.
mjl23,
your concept is completely right if the section is uncracked, but completely wrong if the section is cracked. the steel is about 9 times stiffer than the concrete. so the stress in steel will be about nine times than the stress in surrounding concrete.
if the section is uncracked, the stress at na due to moment is zero, so the stress in the stess at this location should be n*p/a.
this discussion should be equivalent for masonry or concrete. i'm posting my solution with some masonry symbols in case the solution is helpful to others or justifies scrutiny by others.
my solution to determine the actual stress in reinforcing steel due to an applied moment and axial force:
t = depth of masonry beam
fb = m/s - p/a = m (t/2) / i - p/a
η = es / em
ρ = as / (b d)
k = [2 (ρ η) + (ρ η)2]1/2 - (ρ η)
fs = η fb [(1-k)/k]
i believe this addresses the comment of shin25fff"> since η is in place to simulate the equivalent area of steel to masonry.
that is using service load stresses, not ultimate.
mjl23,
the equations that you are writing for k and fs are for cracked sections. where as equation for fb that you have written is for uncracked section.
to decide which equation is to use, you have to find out if the section is cracked or uncracked.
thanks for your help.
shin25
after reviewing an old wang & salmon book, i find where it is mentioned that mc/i is applicable (only?) when using a transformed section, which i guess would be equivalent to the uncracked section.
can you enlighten me and explain why the p/a + mc/i is only applicable for an uncracked section? (something to do with not knowing i?)
of the references i've been through the caveat is always mentioned "only applies to pure bending". which is i guess why the earlier post suggested looking at deconstructing the development of the p-m diagram. i presume i could start with a given p-m and work backwards in the usual construction of the pm diagram.
when you mention needing to know if the section is cracked or not, are you just talking about checking that the concrete/masonry hasn't exceeded the allowable?
structuraleit
i may be missing your point. my question is about calculating the actual stress in the reinforcing, so i don't know why you would mention 'ultimate'.
mc/i assumes the entire section is acting.
in concrete, you assume that the concrete carries no tensile stresses, only the reinforcement carries tension. this is not actually true until the concrete cracks, but the concrete will crack.
__________________
借用达朗贝尔的名言:前进吧,你会得到信心!
[url="http://www.dimcax.com"]几何尺寸与公差标准[/url]
huangyhg离线中   回复时引用此帖
GDT自动化论坛(仅游客可见)
回复


主题工具 搜索本主题
搜索本主题:

高级搜索
显示模式

发帖规则
不可以发表新主题
不可以回复主题
不可以上传附件
不可以编辑您的帖子

vB 代码开启
[IMG]代码开启
HTML代码关闭

相似的主题
主题 主题发起者 论坛 回复 最后发表
c channel beam loads huangyhg 产品功能分析 0 2009-09-07 05:58 PM
buckling stress concentration huangyhg 产品功能分析 0 2009-09-07 05:28 PM
asce 7-98 allowable stress increase huangyhg 产品功能分析 0 2009-09-07 01:18 PM
allowable reinforcing steel stress increases huangyhg 产品功能分析 0 2009-09-07 11:02 AM
allowable fatigue stress huangyhg 产品功能分析 0 2009-09-07 10:57 AM


所有的时间均为北京时间。 现在的时间是 09:22 PM.


于2004年创办,几何尺寸与公差论坛"致力于产品几何量公差标准GD&T | GPS研究/CAD设计/CAM加工/CMM测量"。免责声明:论坛严禁发布色情反动言论及有关违反国家法律法规内容!情节严重者提供其IP,并配合相关部门进行严厉查处,若內容有涉及侵权,请立即联系我们QQ:44671734。注:此论坛须管理员验证方可发帖。
沪ICP备06057009号-2
更多